17=x^2-16x

Solution for 17=x^2-16x equation:

17=x^2-16x

We move all terms to the left:

17-(x^2-16x)=0

We get rid of parentheses

-x^2+16x+17=0

We add all the numbers together, and all the variables

-1x^2+16x+17=0

a = -1; b = 16; c = +17;
Δ = b2-4ac
Δ = 162-4·(-1)·17
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-18}{2*-1}=\frac{-34}{-2}
=+17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+18}{2*-1}=\frac{2}{-2}
=-1
$